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【ybtoj】【BFS】【例题2】山峰和山谷
阅读量:319 次
发布时间:2019-03-04

本文共 1219 字,大约阅读时间需要 4 分钟。

【例题2】山峰和山谷


Link


解题思路

一开始就是有点理解错题意了,对就酱,调了半个小时,一整个就是失语极了

周围只有高的,就是山谷

周围只有矮的,就是山峰
有高有矮,谷、峰都不是
没高没矮是山谷也是山峰


Code

#include 
#include
using namespace std;const int way[8][2] = { { -1, 0}, { 1, 0}, { 0, -1}, { 0, 1}, { -1, -1}, { -1, 1}, { 1, -1}, { 1, 1}};int n, a[1010][1010], v[1010][1010], q[1000100][2], h, t, maxn, minn, ans_max, ans_min;bool check(int x,int y) { return (x > 0 && x <= n && y > 0 && y <= n);}void BFS(int x, int y) { maxn = minn = h = t = 0; q[++t][0] = x, q[t][1] = y; while (h++ < t) { for (int i = 0; i < 8; i++) { int xx = q[h][0] + way[i][0]; int yy = q[h][1] + way[i][1]; if (check(xx, yy)) { if (a[xx][yy] == a[x][y]) { if (!v[xx][yy]) { v[xx][yy] = 1; q[++t][0] = xx, q[t][1] = yy; } }else { if (a[xx][yy] > a[x][y]) maxn++;//统计周围高的 if (a[xx][yy] < a[x][y]) minn++;//统计周围矮的 } } } } if (!minn) ans_min++;//周围没有矮的就是山峰 if (!maxn) ans_max++;//周围没有高的就是山谷}int main() { scanf("%d", &n); for (int i = 1; i <= n; i++) for (int j = 1; j <= n; j++) scanf ("%d", &a[i][j]); for (int i = 1; i <= n; i++) for (int j = 1; j <= n; j++) if (!v[i][j]) BFS(i, j); printf("%d %d", ans_max, ans_min); }

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